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Problem 2.1 (c)

Pre-required Knowledge

  • Maximum Likelihood Estimate formula: From part (a), we know λ^=1Ni=1Nki\hat{\lambda} = \frac{1}{N} \sum_{i=1}^{N} k_i. This corresponds to the total number of hits divided by the total number of cells.

Step-by-Step Answer

  1. Identify the Total Number of Cells (NN): Sum the number of cells for each category: N=229+211+93+35+7+1=576N = 229 + 211 + 93 + 35 + 7 + 1 = 576

  2. Calculate the Total Number of Hits (ki\sum k_i): Multiply the number of hits (kk) by the count of cells with that many hits. Note: For the category "5 and over", we assume the number of hits is exactly 5 based on the standard interpretation of this dataset in literature, as higher counts are extremely unlikely.

    Sum=(0×229)+(1×211)+(2×93)+(3×35)+(4×7)+(5×1)=0+211+186+105+28+5=535\begin{aligned} \text{Sum} &= (0 \times 229) + (1 \times 211) + (2 \times 93) + (3 \times 35) + (4 \times 7) + (5 \times 1) \\ &= 0 + 211 + 186 + 105 + 28 + 5 \\ &= 535 \end{aligned}
  3. Calculate λ^\hat{\lambda}:

    λ^=Total HitsTotal Cells=5355760.928819...\hat{\lambda} = \frac{\text{Total Hits}}{\text{Total Cells}} = \frac{535}{576} \approx 0.928819...
  4. Result: λ^0.929\hat{\lambda} \approx 0.929